A particle of mass 500 g is moving in a straight line with velocity v = b x 5 2 . The work done by the net force during its displacement from x = 0 to x = 4 m is (Take b = 0 . 25 m - 3 2 s - 1 ).

Step-by-step solution

According to the work-energy theorem, work done by all forces will be is equal to the change in kinetic energy. W all = Δ K = 1 2 m b 2 x 2 5 - x 1 5 = 1 2 × 0 . 5 × 1 16 × 4 5 = 16   J