A particle of mass m is moving in a circular path of constant...

{a}_{c} = {k}^{2}r{t}^{2}$</p><p>Or$\dfrac{{v}^{2}}{r} = {k}^{2}r{t}^{2}$Or$v = krt$<br />Therefore, tangential acceleration,${a}_{t} = \dfrac{dv}{dt} = kr$</p><p>Therefore, tangential force,${F}_{t} = m{a}_{t} = mkr$<br /><br />Only tangential force does work.<br /><br />$\text{Power} = {F}_{t}v = \left(mkr\right)\left(krt\right)$\text{⇒Power} = m{k}^{2}{r}^{2}t$