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JEE Main202228 Jun 2022Morning ShiftPhysicsWork, Power and EnergyActual

A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a c is varying with time t as a c = k 2 r t 2 , where k is a constant. The power delivered to the particle by the force acting on it is -

Options

  1. AZero
  2. B2 m k 2 r 2 t
  3. Cm k 2 r 2 t
  4. D2 m k 2 r t

Correct answer

C. m k 2 r 2 t

Step-by-step solution

a c = k 2 r t 2 Or v 2 r = k 2 r t 2 Or v = k r t Therefore, tangential acceleration, a t = d v d t = k r Therefore, tangential force, F t = m a t = m k r Only tangential force does work. Power = F t v = m k r k r t ⇒Power = m k 2 r 2 t

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