JEE Main202225 Jun 2022Evening ShiftPhysicsWork, Power and EnergyActual
For a particle in uniform circular motion, the acceleration a → at any point P R , θ on the circular path of radius R is (when θ is measured from the positive x -axis and v is uniform speed):
Options
- A- v 2 R sin θ i ^ + v 2 R cos θ j ^
- B- v 2 R cos θ i ^ + v 2 R sin θ j ^
- C- v 2 R cos θ i ^ - v 2 R sin θ j ^
- D- v 2 R i ^ + v 2 R j ^
Correct answer
C. - v 2 R cos θ i ^ - v 2 R sin θ j ^
Step-by-step solution
Acceleration of a particle in uniform circular motion is directed towards the centre of the circle and its magnitude is v 2 R . The radius vector is r → = R cos θ i ^ + R sin θ j ^ Therefore, a → = - v 2 R r ^ = v 2 R − cos θ i ^ − sin θ j ^