For a particle in uniform circular motion, the acceleration → a at any point P(R, θ) on the circular path of radius R is (when θ is measured from the positive x -axis and v is uniform speed):

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Correct answer: C. - v ^ 2 R cosθ ^ i - v ^ 2 R sinθ ^ j

For a particle in uniform circular motion, the acceleration → a at any point P(R, θ) on the circular path of radius R

Acceleration of a particle in uniform circular motion is directed towards the centre of the circle and its magnitude is $\dfrac{{v}^{2}}{R}$ . The radius vector is $\overset{\to}{r} = Rcos\theta\overset{^}{i} + Rsin\theta\overset{^}{j}$

Therefore, $\overset{\to}{a} = - \dfrac{{v}^{2}}{R}\overset{^}{r} = \dfrac{{v}^{2}}{R}\left(- cos\theta\overset{^}{i} - sin\theta\overset{^}{j}\right)$

For a particle in uniform circular motion, the acceleration → a at...

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