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JEE Main 202225 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
25 June
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2022 · 25 June · Morning Shift · Physics · Work, Power and Energy

A 0 . 5kg block moving at a speed of 12 ms ^ - 1 compresses a...

A 0.5kg0 . 5kg block moving at a speed of 12ms−112{ms}^{- 1} compresses a spring through a distance 30cm30cm when its speed is halved. The spring constant of the spring will be _____ Nm−1{Nm}^{- 1}

Correct answer

0

Step-by-step solution

Given: Mass of the block m=500gm = 500g, initial velocity of the block u=12ms−1u = 12m{s}^{- 1}, and final velocity of the block v=u2=6ms−1v = \dfrac{u}{2} = 6m{s}^{- 1}.

As non-conservative forces are not acting on the system we can conserve energy.

Thus, loss in kinetic energy of block = Gain in potential energy of spring

12mu2−12mv2=12kx2\dfrac{1}{2}m{u}^{2} - \dfrac{1}{2}m{v}^{2} = \dfrac{1}{2}k{x}^{2}

12×0.5×122−12×0.5×62=12k×0.32\dfrac{1}{2} \times 0 . 5 \times {12}^{2} - \dfrac{1}{2} \times 0 . 5 \times {6}^{2} = \dfrac{1}{2}k \times 0 . {3}^{2}

k=600Nm−1k = 600N{m}^{- 1}

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