A ball of mass 100g is dropped from a height h = 10cm on a platform fixed at the top of a vertical spring (as shown in figure). The ball stays on the platform and the platform is depressed by a distance (h)/(2) . The

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A ball of mass 100g is dropped from a height h = 10cm on a platform fixed at the top of a vertical spring (as shown in

Loss in the gravitational potential energy of the ball= gain in the potential energy by the spring

$- ∆ P{E}_{gravitational} = ∆ P{E}_{spring}$

$mg\left(h + \dfrac{h}{2}\right) = \dfrac{1}{2}k\left(\dfrac{h}{2}\right)2⇒mg\dfrac{3h}{2} = \dfrac{kh^{2}}{8}$

$⇒ k = \dfrac{12mg}{h} = \dfrac{12 \times 0 . 1 \times 10}{0 . 1} = 120Nm^{- 1}$

A ball of mass 100g is dropped from a height h = 10cm on a platform...

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