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JEE Main 202127 JulyEvening Shift
Exam
JEE Main
Year
2021
Date
27 July
Shift
Evening Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2021 · 27 July · Evening Shift · Physics · Work, Power and Energy

An automobile of mass m accelerates starting from the origin and...

An automobile of mass mm accelerates starting from the origin and initially at rest, while the engine supplies constant power PP. The position is given as a function of time by:

Options

  1. A(9P8m)12t32\left(\dfrac{9P}{8m}\right)\dfrac{1}{2}t\dfrac{3}{2}
  2. B(8P9m)12t23\left(\dfrac{8P}{9m}\right)\dfrac{1}{2}t\dfrac{2}{3}
  3. C(9m8P)12t32\left(\dfrac{9m}{8P}\right)\dfrac{1}{2}t\dfrac{3}{2}
  4. D(8P9m)12t32\left(\dfrac{8P}{9m}\right)\dfrac{1}{2}t\dfrac{3}{2}

Correct answer

D. (8P9m)12t32\left(\dfrac{8P}{9m}\right)\dfrac{1}{2}t\dfrac{3}{2}

Step-by-step solution

P=constP = const

P=FV=mv2dvdxP = {F}_{V} = \dfrac{m{v}^{2}dv}{dx}

∫0xPmdx=∫0vv2dv{∫}_{0}^{x}\dfrac{P}{m}dx = {∫}_{0}^{v}{v}^{2}dv

Pxm=v33\dfrac{Px}{m} = \dfrac{{v}^{3}}{3}

\left(\dfrac{3Px}{m}\right)\dfrac{1}{3} = v = \dfrac{dx}{dt}</p><p>(3Pm)13∫0tdt=∫0xx−13dx</p><p>\left(\dfrac{3P}{m}\right)\dfrac{1}{3}{∫}_{0}^{t}dt = {∫}_{0}^{x}{x}^{- \dfrac{1}{3}}dx

⇒x=(8P9m)12t32⇒ x = \left(\dfrac{8P}{9m}\right)\dfrac{1}{2}t\dfrac{3}{2}

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