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JEE Main 202125 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
25 February
Shift
Morning Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2021 · 25 February · Morning Shift · Physics · Work, Power and Energy

The potential energy (U) of a diatomic molecule is a function...

The potential energy (U)\left(U\right) of a diatomic molecule is a function dependent on rr (interatomic distance)asU=αr10−βr5−3as U = \dfrac{\alpha}{{r}^{10}} - \dfrac{\beta}{{r}^{5}} - 3 where, α\alpha and β\beta are positive constants. The equilibrium distance between two atoms will be (2αβ)ab,\left(\dfrac{2\alpha}{\beta}\right)\dfrac{a}{b}, where a=a =______ .

Correct answer

0

Step-by-step solution

For equilibrium

dUdr=0\dfrac{dU}{dr} = 0

−10αr11+5βr6=0\dfrac{- 10\alpha}{{r}^{11}} + \dfrac{5\beta}{{r}^{6}} = 0

5βr6=10αr11\dfrac{5\beta}{{r}^{6}} = \dfrac{10\alpha}{{r}^{11}}

r5=2αβ{r}^{5} = \dfrac{2\alpha}{\beta}

r5=2αβ{r}^{5} = \dfrac{2\alpha}{\beta}

r=(2αβ)15a=1r = \left(\dfrac{2\alpha}{\beta}\right)\dfrac{1}{5}a = 1

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