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JEE Main 202124 FebruaryEvening Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Evening Shift
Subject
Physics
Chapter
Work, Power and Energy

JEE Main 2021 · 24 February · Evening Shift · Physics · Work, Power and Energy

Two solids A and B of mass 1kg and 2kg respectively are moving with...

Two solids AA and BB of mass 1kg1kg and 2kg2kg respectively are moving with equal linear momentum. The ratio of their kinetic energies (K.E.){\left(K . E .\right)}_{A}: {\left(K . E .\right)}_{B} will be A1,\dfrac{A}{1}, so the value of AA will be _________.

Correct answer

0

Step-by-step solution

Kinetic energy K=P22m,(PA=PB)K = \dfrac{{P}^{2}}{2m}, \left({P}_{A} = {P}_{B}\right)

K∝1mK ∝ \dfrac{1}{m}

KAKB=mBmA\dfrac{{K}_{A}}{{K}_{B}} = \dfrac{{m}_{B}}{{m}_{A}}

=21= \dfrac{2}{1}

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