JEE Main20203 Sep 2020Morning ShiftPhysicsWork, Power and EnergyActual
A cricket ball of mass 0 . 15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball applies a constant force F on the ball and moves horizontally a distance of 0 . 2 m while launching the ball, the value of F ( in N ) is g = 10 m s - 2
Correct answer
0
Step-by-step solution
From work energy theorem F 0 . 2 - mg 20 = 0 F = mg 20 0 . 2 = mg 200 2 = 0 . 15 × 10 × 200 2 = 150 . 00   N