In a reactor, 2 kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200 MeV . Given that the Avogadro number, N = 6 . 023 × 10 26 per kilo mole and 1 eV = 1 . 6 × 10 - 19 J . The power output of the rea

Question

In a reactor, 2 kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200 MeV . Given that the Avogadro number, N = 6 . 023 &#215; 10 26 per kilo mole and 1 eV = 1 . 6 &#215; 10 - 19 J . The power output of the reactor is close to:

Quantrex Academy · Accepted Answer

Correct answer: B. 60 &#160; MW

P = E t = 2 235 &#215; 6 . 023 &#215; 10 26 &#215; 200 &#215; 1 . 6 &#215; 10 - 19 30 &#215; 24 &#215; 60 &#215; 60 = 60 &#160; MW

In a reactor, 2 kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200 MeV . Given that the Avogadro number, N = 6 . 023 × 10 26 per kilo mole and 1 eV = 1 . 6 × 10 - 19 J . The power output of the reactor is close to:

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In a reactor, 2 kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200 MeV . Given that the Avogadro number, N = 6 . 023 &#215; 10 26 per kilo mole and 1 eV = 1 . 6 &#215; 10 - 19 J . The power output of the reactor is close to:

Options

Correct answer

Step-by-step solution

More from Work, Power and Energy

In a reactor, 2 kg of U 235 92 fuel is fully used up in 30 days. The energy released fission is 200 MeV . Given that the Avogadro number, N = 6 . 023 × 10 26 per kilo mole and 1 eV = 1 . 6 × 10 - 19 J . The power output of the reactor is close to: