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JEE Main20199 Apr 2019Evening ShiftPhysicsWork, Power and EnergyActual

A wedge of mass M = 4 m lies on a frictionless plane. A particle of mass m approaches the wedge with speed v . There is no friction between the particle and the plane or between the particle and the wedge. The maximum height climbed by the particle on the wedge is given by:

Options

  1. Av 2 g
  2. Bv 2 2 g
  3. C2 v 2 5 g
  4. D2 v 2 7 g

Correct answer

C. 2 v 2 5 g

Step-by-step solution

From conservation of linear momentum, m v = 4 m + m v f v f = v 5 From conservation of mechanical energy, 1 2 m v 2 = 1 2 4 m + m v f 2 + m g h v 2 = 5 v f 2 + 2 g h v 2 = 5 × v 5 2 + 2 g h h = 2 v 2 5 g

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