A particle of mass 20 g is released with an initial velocity 5 m s - 1 along the curve from the point A , as shown in the figure. The point A is at height h from point B . The particle slides along the frictionless surface. When the particle reaches point B , its angular momentum about O will be: (Take g = 10 m s - 2 )

Step-by-step solution

Applying conservation of energy, m g h = 1 2 m v B 2 - 1 2 m v A 2 ⇒ v B = 2 g h + v A 2 ⇒ v B = 2 × 10 × 10 + 25 ⇒ v B = 15   m   s - 1 Angular momentum about O , L O = m v B h + a ⇒ L O = 20 × 10 - 3 × 15 × 20   kg   m 2   s - 1 ⇒ L O = 6   kg   m 2   s - 1