A time dependent force F = 6 t acts on a particle of mass 1 kg . If the particle starts from the rest, the work done by the force during the first 1 sec will be:

Step-by-step solution

m = 1   kg F = 6 t ∴     a = F m = 6 t d v d t = 6 t ∴   ∫ 0 v 0 d v = ∫ 0 1 6 t · d t ∴     v 0 = 6 × 1 2 2 = 3   m   s - 1 Δ w = k f - k i = 1 2 × 1 × 9 - 0 = 4.5   J