A bullet fired into a fixed target loses half of its velocity after penetrating 3 ~cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

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Correct answer: D. 1.0 ~cm

F .3= 1 2 m v^2- 1 2 m v^2 4 F(3+x)= 1 2 m v^2x=1 ~cm

A bullet fired into a fixed target loses half of its velocity after penetrating 3 ~cm . How much further it will penetrate before coming to rest assuming that it faces constant resistance to motion?

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