JEE Main2004PhysicsWork, Power and EnergyActual
A force F =(5 i +3 j +2 k ) N is applied over a particle which displaces it from its origin to the point r =(2 i - j ) m . The work done on the particle in joules is
Options
- A-7
- B+7
- C+10
- D+13
Correct answer
B. +7
Step-by-step solution
Work done, W = F s Here s = r _f- r _i=(2 i - j ) W=(5 i +3 j +2 k )(2 i - j )=10-3=7 ~J