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JEE Main2004PhysicsWork, Power and EnergyActual

A force F =(5 i +3 j +2 k ) N is applied over a particle which displaces it from its origin to the point r =(2 i - j ) m . The work done on the particle in joules is

Options

  1. A-7
  2. B+7
  3. C+10
  4. D+13

Correct answer

B. +7

Step-by-step solution

Work done, W = F s Here s = r _f- r _i=(2 i - j ) W=(5 i +3 j +2 k )(2 i - j )=10-3=7 ~J

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