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JIPMER 2016
Exam
JIPMER
Year
2016
Subject
Chemistry
Chapter
General Principles and Processes of Isolation of Metals

JIPMER 2016 · Chemistry · General Principles and Processes of Isolation of Metals

For the formation of Cr_2 O_3 and Al_2 O_3 , values of Δ_f G^ are...

For the formation of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 and Al2O3\mathrm{Al}_2 \mathrm{O}_3, values of ΔfG∘\Delta_f G^{\circ} are 540 kJ mol−1540 \mathrm{~kJ} \mathrm{~mol}^{-1} and −827 kJ mol−1-827 \mathrm{~kJ} \mathrm{~mol}^{-1} respectively. What will be the possibility for reaction of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 by Al ?

Options

  1. AReduction of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 by Al will take place
  2. BOxidation of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 by Al will take place
  3. CNeither oxidation nor reduction will take place
  4. DReaction is not feasible

Correct answer

A. Reduction of Cr2O3\mathrm{Cr}_2 \mathrm{O}_3 by Al will take place

Step-by-step solution

2Cr+32O2⟶Cr2O3;ΔfG∘=−540 kJ mol−1…2Al+32O2⟶Al2O3;ΔfG∘=−827 kJ mol−1…\begin{aligned} & 2 \mathrm{Cr}+\frac{3}{2} \mathrm{O}_2 \longrightarrow \mathrm{Cr}_2 \mathrm{O}_3 ; \Delta_f \mathrm{G}^{\circ}=-540 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots \\ & 2 \mathrm{Al}+\frac{3}{2} \mathrm{O}_2 \longrightarrow \mathrm{Al}_2 \mathrm{O}_3 ; \Delta_f \mathrm{G}^{\circ}=-827 \mathrm{~kJ} \mathrm{~mol}^{-1} \ldots\end{aligned} Substrating equation (i) from (ii) 2Al+Cr2O3⟶Al2O3+2CrΔrG=[−827−(−540)]kJmol−1=−287 kJ mol−1\begin{gathered}2 \mathrm{Al}+\mathrm{Cr}_2 \mathrm{O}_3 \longrightarrow \mathrm{Al}_2 \mathrm{O}_3+2 \mathrm{Cr} \\ \Delta_r G=[-827-(-540)] \mathrm{kJ} \mathrm{mol}^{-1}=-287 \mathrm{~kJ} \mathrm{~mol}^{-1}\end{gathered} because for the reduction by AlA l, value of ΔG∘\Delta G^{\circ} is negative, therefore reaction is feasible.
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