AP EAMCET201921 Apr 2019Evening ShiftChemistryp Block Elements (Group 13 & 14)Actual
Match the following. List - I Reaction List - II Catalyst ( A ) N 2 ( g ) + 3 H 2 ( g ) ⟶ 2 NH 3 ( g ) ( I ) Ni ( B ) 2 H 2 ( g ) + O 2 ( g ) ⟶ 2 H 2 O ( l ) ( II ) Pt ( C ) CO ( g ) + 3 H 2 ( g ) ⟶ CH 4 ( g ) + H 2 O ( g ) ( III ) ZnO - Cr 2 O 3 ( D ) CO ( g ) + 2 H 2 ( g ) ⟶ CH 3 OH ( g ) ( IV ) Fe The correct answer is:
Options
- AA B C D III II I IV
- BA B C D IV III II I
- CA B C D IV II I III
- DA B C D IV I III II
Correct answer
C. A B C D IV II I III
Step-by-step solution
The catalyst for the reactions is, List-I List-II N 2 ( g ) + 3 H 2 ( g ) → 2 NH 3 ( g ) In Haber's process N 2 and   H 2 are combined in 1 : 3 ratio at 200   atm pressure and high temperature 400 - 450 ° C . Fe 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) On passing Oxygen over Hydrogen adsorbed platinum, it gives Water. Pt CO ( g ) + 3 H 2 ( g ) → CH 4 ( g ) + H 2 O ( g ) In presence of Ni , they undergo complete reduction to give methane. Ni CO ( g ) + 2 H 2 ( g ) → CH 3 OH