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JIPMER 2012
Exam
JIPMER
Year
2012
Subject
Chemistry
Chapter
Practical Chemistry

JIPMER 2012 · Chemistry · Practical Chemistry

Ammonia is a Lewis base and it forms complexes with many cations....

Ammonia is a Lewis base and it forms complexes with many cations. Which one of the following cations does not form a complex with ammonia?

Options

  1. AAg+\mathrm{Ag}^{+}
  2. BCu2+\mathrm{Cu}^{2+}
  3. CCd2+\mathrm{Cd}^{2+}
  4. DPb2+\mathrm{Pb}^{2+}

Correct answer

D. Pb2+\mathrm{Pb}^{2+}

Step-by-step solution

Ammonia is a Lewis base. It forms complexes with transition elements like Ag+,Cu2+\mathrm{Ag}^{+}, \mathrm{Cu}^{2+} and Cd2+\mathrm{Cd}^{2+} while it does not form complex with Pb2+\mathrm{Pb}^{2+} because Pb is not a transition element. AgCl+2NH4OH⟶[Ag(NH3)2]Cl+2H2O\mathrm{AgCl}+2 \mathrm{NH}_4 \mathrm{OH} \longrightarrow\left[\mathrm{Ag}\left(\mathrm{NH}_3\right)_2\right] \mathrm{Cl}+2 \mathrm{H}_2 \mathrm{O}CuSO4+4NH4OH⟶[Cu(NH3)4]SO4+4H2O\begin{aligned} & \mathrm{CuSO}_4+4 \mathrm{NH}_4 \mathrm{OH} \longrightarrow {\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right] \mathrm{SO}_4 } +4 \mathrm{H}_2 \mathrm{O}\end{aligned}CdSO4+4NH4OH⟶[Cd(NH3)4]SO4+4H2O\begin{aligned} & \mathrm{CdSO}_4+4 \mathrm{NH}_4 \mathrm{OH} \longrightarrow\left[\mathrm{Cd}\left(\mathrm{NH}_3\right)_4\right] \mathrm{SO}_4 +4 \mathrm{H}_2 \mathrm{O} \end{aligned}$$
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