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JIPMER 2015
Exam
JIPMER
Year
2015
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

JIPMER 2015 · Chemistry · Some Basic Concepts of Chemistry

Which of the following is correctly arranged in order of increasing...

Which of the following is correctly arranged in order of increasing weight?

Options

  1. A0.0105 equivalent of H2C2O4⋅2H2O<0.625 g\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O} \lt 0.625 \mathrm{~g} of Fe<0.006 g\mathrm{Fe} \lt 0.006 \mathrm{~g} atom of Ag<6.0×1021\mathrm{Ag} \lt 6.0 \times 10^{21} atoms of Zn
  2. B0.625 g of Fe<0.0105\mathrm{Fe} \lt 0.0105 equivalent of H2C2O4⋅2H2O<6.0×1021\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O} \lt 6.0 \times 10^{21} atoms of Zn<\mathrm{Zn} \lt 0.006 g atom of Ag
  3. C0.625 g of Fe<6.0×1021\mathrm{Fe} \lt 6.0 \times 10^{21} atoms of Zn<0.006 g\mathrm{Zn} \lt 0.006 \mathrm{~g} atom of Ag<0.0105\mathrm{Ag} \lt 0.0105 equivalent of H2C2O4⋅2H2O\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}
  4. D0.0105 equivalent of H2C2O4⋅2H2O<0.006 g\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O} \lt 0.006 \mathrm{~g} atom of Ag<6.0×1021\mathrm{Ag} \lt 6.0 \times 10^{21} atoms of Zn<0.625 g\mathrm{Zn} \lt 0.625 \mathrm{~g} of Fe

Correct answer

C. 0.625 g of Fe<6.0×1021\mathrm{Fe} \lt 6.0 \times 10^{21} atoms of Zn<0.006 g\mathrm{Zn} \lt 0.006 \mathrm{~g} atom of Ag<0.0105\mathrm{Ag} \lt 0.0105 equivalent of H2C2O4⋅2H2O\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}

Step-by-step solution

0.625gFe0.0105 eq. of H2C2O4⋅2H2O=0.0105×63=0.66g( Eq. wt =63)6×1021 atoms of Zn=6×10216.023×1023×65=0.647g\begin{aligned} & 0.625 \mathrm{ g} \mathrm{Fe} \\ & 0.0105 \text{ eq. of } \mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}=0.0105 \times 63 \\ & \quad=0.66 \mathrm{ g} \quad(\text{ Eq. wt }=63) \\ & 6 \times 10^{21} \text{ atoms of } \mathrm{Zn}=\frac{6 \times 10^{21}}{6.023 \times 10^{23}} \times 65=0.647 \mathrm{ g}\end{aligned}0.006 g atom of \mathrm{Ag}=0.006 \times 108=0.648 \mathrm{ g} \thereforeIncreasingorderofweightIncreasing order of weight\mathrm{Fe}<<\mathrm{Zn}<<\mathrm{Ag}<<\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4 \cdot 2 \mathrm{H}_2 \mathrm{O}$
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