2 KHCO ₃ + CO ₂+ H ₂ O find amount of gases formed (in lit). When amount of KHCO ₃ is 33 gm .

Step-by-step solution

The given reaction is as follows 2 KHCO ₃ K ₂ CO ₃( ~g )+ CO ₂( ~g )+ H ₂ O (l) 2 moles of KHCO ₃ gives =1 ~mol of K ₂ CO ₃ 1 moles of KHCO ₃ gives =1 / 2 ~mol of K ₂ CO ₃ 33 gm ( 33 100 ~mol ) of KHCO ₃ gives = 33 200 mol of K ₂ CO ₃ Similarly, 33 gm ( 33 100 ~mol ) of KHCO ₃ gives = 33 200 ~mol of CO ₂ Total moles of gases = 33 200 + 33 200 = 66 200 ~mol aligned 1 ~mol of gas & =224 l volume 66 200 ~mol of gas & = 66 200 22.4=7.46 l . aligned