The volume of water to be added to 100 cm^3 of 0.5 NH_2 SO_4 to get decinormal concentraction is

Correct answer: D. 400 ~cm^3 N_1 V_1=N_2 V_2 Given, N_1=0.5 ~N, ~N_2=0.1 ~N V_1=100 ~cm^3, V_2=? 0.5 × 100=0.1 × V_2 V_2=500 ~cm^3 (Total final volume) Volume to be added =500-100=400 ~cm^3

JIPMER 2017

Exam: JIPMER
Year: 2017
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

JIPMER 2017 · Chemistry · Some Basic Concepts of Chemistry

The volume of water to be added to 100 cm^3 of 0.5 NH_2 SO_4 to get...

The volume of water to be added to 100

\mathrm{cm}^3

0.5 \mathrm{NH}_2 \mathrm{SO}_4

to get decinormal concentraction is

Options

A $100 \mathrm{~cm}^3$
B $450 \mathrm{~cm}^3$
C $500 \mathrm{~cm}^3$
D $400 \mathrm{~cm}^3$

Correct answer

D. $400 \mathrm{~cm}^3$

Step-by-step solution

\because N_1 V_1=N_2 V_2

Given,

N_1=0.5 \mathrm{~N}, \mathrm{~N}_2=0.1 \mathrm{~N}

V_1=100 \mathrm{~cm}^3, V_2=?

\therefore 0.5 \times 100=0.1 \times V_2

V_2=500 \mathrm{~cm}^3

(Total final volume)

\therefore

Volume to be added

=500-100=400 \mathrm{~cm}^3

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