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AP EAMCET20226 Jul 2022Evening ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Which of the following compound has reducing character?

Options

  1. ASO ₂
  2. BTeO ₂
  3. CSO ₃
  4. DTeO ₃

Correct answer

A. SO ₂

Step-by-step solution

SO ₂ shows reducing character because +6 oxidation state of S is more stable than its +4 oxidation state. TeO ₂ shows oxidising character because its +4 oxidation state is more stable due to inert pair effect. SO ₃ and TeO ₃ do not shows reducing character because S and Te are in +6 oxidation state, which is their highest oxidation state.

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