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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Physics
Chapter
Work, Power and Energy

JIPMER 2019 · Physics · Work, Power and Energy

A particle of mass 7 kg is executing circular motion with time...

A particle of mass 7 kg is executing circular motion with time period of 11 sec . Find out centripetal force, if radius of circle is 10 m .

Options

  1. A307 N\frac{30}{7} \mathrm{~N}
  2. B407 N\frac{40}{7} \mathrm{~N}
  3. C30 N
  4. D1607 N\frac{160}{7} \mathrm{~N}

Correct answer

D. 1607 N\frac{160}{7} \mathrm{~N}

Step-by-step solution

Given, Time period (T)=11sec(\mathrm{T})=11 \mathrm{sec}, mass of particle (m)=7 kg(\mathrm{m})=7 \mathrm{~kg} and \quad radius (r)=10 m(\mathrm{r})=10 \mathrm{~m} ∴\therefore \quad Speed of particle, v=2πrT=2×227×1011v=\frac{2 \pi r}{T}=\frac{2 \times \frac{22}{7} \times 10}{11} =407 m/s=\frac{40}{7} \mathrm{~m} / \mathrm{s} ∴\therefore Centripetal force, F=mv2r=7×407×40710=1607 N\mathrm{F}=\frac{\mathrm{mv}^2}{\mathrm{r}}=\frac{7 \times \frac{40}{7} \times \frac{40}{7}}{10}=\frac{160}{7} \mathrm{~N}
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