A particle is moving with 10 ~m / s in a circle of radius 5 m , find out magnitude of average velocity if particle moved by 60^ in 1 sec.

Step-by-step solution

aligned & Given, velocity of particle v=10 ~m / s & radius (r^ )=5 ~m & Angular displacement ( )=60^ & =60 180 rad & = 3 rad & aligned When particle moves at an angle of 60^ , then according to figure, displacement AB is equal to radius r because it forms an equilateral triangle. Average velocity = displacement AB time = r ^ 1 =5 ~m / s