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JIPMER 2019
Exam
JIPMER
Year
2019
Subject
Physics
Chapter
Work, Power and Energy

JIPMER 2019 · Physics · Work, Power and Energy

A man applying force of 20 N on an object at an angle of 60^ from...

A man applying force of 20 N on an object at an angle of 60∘60^{\circ} from the horizontal. If object moved by 20 m in horizontal direction, then work done by the force on the object is

Options

  1. A300 J
  2. B400 J
  3. C100 J
  4. D200 J

Correct answer

D. 200 J

Step-by-step solution

Given, force, f=20 N\mathrm{f}=20 \mathrm{~N}, angle θ=60∘\theta=60^{\circ} and displacement (s)=20 m(\mathrm{s})=20 \mathrm{~m}, ∴\therefore Work done by the force W=fscos⁡θ=20×20×cos⁡60∘=20×20×12=200 J\begin{aligned} \mathrm{W} & =\mathrm{fs} \cos \theta=20 \times 20 \times \cos 60^{\circ}=20 \times 20 \times \frac{1}{2} \\ & =200 \mathrm{~J} \end{aligned}
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