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JIPMER 2014
Exam
JIPMER
Year
2014
Subject
Physics
Chapter
Work, Power and Energy

JIPMER 2014 · Physics · Work, Power and Energy

A particle of mass 100 g is thrown vertically upward with a speed...

A particle of mass 100 g is thrown vertically upward with a speed of 5 m/s5 \mathrm{~m} / \mathrm{s}. The work done by the force of gravity during the time the particle goes up is

Options

  1. A−0.5-0.5 J
  2. B−1.25-1.25 J
  3. C1.251.25 J
  4. D0.50.5 J

Correct answer

B. −1.25-1.25 J

Step-by-step solution

The height (h)(h) transversed by particle while going up is n=u22g=252×9.8n=\frac{u^2}{2 g}=\frac{25}{2 \times 9.8} Work done by gravity force =mg⋅h=m \mathrm{g} \cdot \mathrm{h} =0.1×g×252×9.8cos⁡180∘=0.1 \times g \times \frac{25}{2 \times 9.8} \cos 180^{\circ} (angle between force and displacement is 180∘)180^{\circ}) ∴W=−0.1×252=−1.25\therefore \quad W=-0.1 \times \frac{25}{2}=-1.25
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