Exam

JIPMER

Year

2012

Subject

Physics

Chapter

Work, Power and Energy

JIPMER 2012 · Physics · Work, Power and Energy

The work done by a force acting on a body is as shown in the graph....

The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

Step-by-step solution

Work done $W=$ Area $A B C D E F G A$ = Area $A B C D G+$ Area $D E F G$ $=\frac{1}{2} \times(15+10) \times 10+\frac{1}{2} \times(10+20) \times 5$ $=125+75=200 \mathrm{~J}$