Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JIPMER 2011
Exam
JIPMER
Year
2011
Subject
Physics
Chapter
Work, Power and Energy

JIPMER 2011 · Physics · Work, Power and Energy

A ball of mass 2 kg moving with velocity 3 ~m / s , collides with...

A ball of mass 2 kg moving with velocity 3 m/s3 \mathrm{~m} / \mathrm{s}, collides with spring of natural length 2 m and force constant 144 N/m144 \mathrm{~N} / \mathrm{m}. What will be length of compressed spring?A ball of mass 2 kg moving with velocity 3 ~m / s , collides with spring of natural length 2 m and force constant 144

Options

  1. A2 m
  2. B1.5 m
  3. C1 m
  4. D0.5 m

Correct answer

B. 1.5 m

Step-by-step solution

Let spring is compressed by a length xx. Kinetic energy of ball = Potential energy of spring ie,12mv2=12kx2i e, \quad \frac{1}{2} m v^2=\frac{1}{2} k x^2 Given, m=2 kg,v=3 m/s,k=144 N/m\quad m=2 \mathrm{~kg}, v=3 \mathrm{~m} / \mathrm{s}, k=144 \mathrm{~N} / \mathrm{m} ∴12×2×(3)2=12×144×x2\therefore \quad \frac{1}{2} \times 2 \times(3)^2=\frac{1}{2} \times 144 \times x^2 A ball of mass 2 kg moving with velocity 3 ~m / s , collides with spring of natural length 2 m and force constant 144 ∴x=972=122 m\therefore \quad x=\sqrt{\frac{9}{72}}=\frac{1}{2 \sqrt{2}} \mathrm{~m} Hence, length of compressed spring =2−122=2-\frac{1}{2 \sqrt{2}} =42−122=\frac{4 \sqrt{2}-1}{2 \sqrt{2}} =1.5 m=1.5 \mathrm{~m}
Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JIPMER PYQs