1000 N force is required to lift a hook and 10000 N force is requires to lift a load slowly. Find power required to lift hook with load with speed v =0.5 ~m / s

Step-by-step solution

Net force required to lift a hook and load, F _ net =1000+10000=11000 ~N Power required to lift hook, P = W t aligned W & = F _ net d P t & = F _ net d P & = F _ net d t = F _ net ( d t )= F _ net V [ Here, v = d t ] aligned or P =11000 0.5=5500 ~W =5.5 ~kW