Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JIPMER2004PhysicsWork, Power and Energy

A particle moves from position r ₁=3 i +2 j -6 k to position r ₂=14 i +13 j +9 k under action of force F =4 i + j +3 k N . The work done will be:

Options

  1. A100 J
  2. B50 J
  3. C200 J
  4. D75 J

Correct answer

A. 100 J

Step-by-step solution

Using the formula for work done W= F r = F ( r ₂ - r ₁ ) array r W=(4 i + j +3 k ) (14 i +13 j +9 k ) -3 i -2 j +6 k ) array aligned & W=(4 i + j +3 k ) (11 i +11 j +15 k ) & W=44+11+45=100 joule aligned

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JIPMER PYQs