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AP EAMCET202023 Sep 2020Morning ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual

Calculate the mass of AgCl precipitated, when 25 ml of 35 % solution of AgNO 3 and 25 ml of 11 . 6 % solution of NaCl are mixed is

Options

  1. A7   g
  2. B17   g
  3. C20   g
  4. D15   g

Correct answer

A. 7   g

Step-by-step solution

AgNO 3   ( aq ) + NaCl   ( aq ) → AgCl   ( s ) + NaNO 3   ( aq ) The above equation is balanced, and we can see that when one mole of AgNO 3 and one mole of NaCl react then one mole of AgCl is precipitated. So, the reactant which is present in lesser quantity determines the amount of AgCl formed. 25   ml of 35 %   AgNO 3 = 25 × 35 100 = 8 . 75   g of AgNO 3 25   ml of 11 . 6 %   NaCl = 25 × 11 . 6 100 = 2 . 9   g of NaCl As 1 mole NaCl = 58 . 5 &#160

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