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KCET2024ChemistryAlcohols Phenols and Ethers

8.8 g of monohydric alcohol added to ethyl magnesium iodide in ether liberates 2240 ~cm ^3 of ethane at STP. This monohydric alcohol when oxidised using pyridinium-chloro-chromate, forms a carbonyl compound that answers silver mirror test (Tollen's test). The monohydric alcohol is

Options

  1. Abutan-2-ol
  2. B2, 2-dimethyl propan-1-ol
  3. Cpentan-2-ol
  4. D2, 2-dimethyl ethan-1-ol

Correct answer

B. 2, 2-dimethyl propan-1-ol

Step-by-step solution

Given that, 8.8 g of monohydric alcohol liberates 2240 ~cm ^3 of ethane. So, 88 g of monohydric alcohol will liberate 22400 ~cm ^3 (STP) Now, the carbonyl compound that can oxidise Tollens reagent is aldehyde and it is the oxidising product of 1^ alcohol. So, among the given options 2, 2-dimethyl propan-1-ol (molecular mass =88 ) is the required monohydric alcohol.

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