The product formed during the following reaction are

Step-by-step solution

The reaction involved is This is because the reaction occurs by ( S_ N I ) mechanism. The formation of products is governed by the stability of the carbocation formed from the cleavage of ( C - O ) bond in the protonated ether (oxonium ion). Since tert-butyl carbocation ( [ ( CH ₃ )₃ C ⁺ ] )is more stable than the methyl carbocation ( CH ₃⁺ ) Therefore, cleavage of ( C - O ) bond gives a more stable carbocation ( [ ( CH ₃ )₃ C ⁺ ] )and methanol as products. Then iodide ion ( (I⁻ ) )attacks tert-butyl carbocation to