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KCET2025ChemistryChemical Bonding and Molecular Structure

Match List-I with List-II and select the correct option: array |l|l|l|l| & List-I (Molecule / ion & & List-II (Bond order) 1 . & NO & (i) & 15 2. & CO & (ii) & 2.0 3. & O ₂⁻ & (iii) & 2.5 4. & O ₂ & (iv) & 3.0 array

Options

  1. Aa-iii, b-iv, c-i, d-ii
  2. Ba-i, b-iv, c-iii, d-ii
  3. Ca-ii, b-iii, c-iv, d-i
  4. Da-iv, b-iii, c-ii, d-i

Correct answer

A. a-iii, b-iv, c-i, d-ii

Step-by-step solution

Bond order = 1 2 [no. of bonding - no. of bonding electrons] For NO molecule aligned & BO =(8-3) / 2=2.5 & CO - 1 2 [10-4]=3.0 & O ₂⁻¹- 1 2 [6-3]=1.5 & O ₂- 1 2 [6-2]=2.0 aligned

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