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KCET2018ChemistryChemical Bonding and Molecular Structure

The state of hybrid orbitals of carbon in ( CO ₂, CH ₄ ) and ( CO ₃ ²⁻ ) respectively is

Options

  1. A( sp ³, sp ² ) and ( sp )
  2. B( s p³, s p ) and ( s p² )
  3. C( sp , sp ³ ) and ( sp ² )
  4. D( sp ², sp ³ ) and ( sp )

Correct answer

C. ( sp , sp ³ ) and ( sp ² )

Step-by-step solution

Using the formula State of hybridisation = (V+M-C+A) 2 Where, V = No. of valance electrons. M = No. of monovalent atoms. C = Cationic charge. A = Anionic charge. CO ₂= 4+0 2 = 4 2 =2 s p h y b r i d i z e d CH ₄= 4+4 2 = 8 2 =4 s p³ hybridized. CO ₃ ²⁻= 4+0+2 2 = 6 2 3 s p² hybridized.

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