The increasing order of bond order of ( O ₂, O ₂⁺, O ₂⁻ ), and ( O ₂⁻⁻ )is

Step-by-step solution

Electronic configuration of ( O ₂ ) : ( 1 s² ^ * 1 s² 2 s² ^ * 2 s² 2 p_ z ² 2 p_ x ²= 2 p_ y ² ^ * 2 p_ x ¹= ^ * 2 p_ y ¹ ) Bond order ( = [ No. of bonding e⁻ s- No. of anti-bonding e⁻ s ] 2 ) [ array l O₂= 1 2 (10-6)=2 O₂⁻= 1 2 (10-7)=1.5 O₂²⁻= 1 2 (10-8)=1 O₂⁺= 1 2 (10-5)= 5 2 =2.5 array ] Therefore, the correct decreasing order of bond order is ( O ₂ ⁺> O ₂> O ₂ ⁻> O ₂ ²⁻ ).