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KCET2024ChemistryClassification of Elements and Periodicity in Properties

A pair of isoelectronic species having bond order of one is

Options

  1. AN ₂, CO
  2. BN ₂, NO ⁺
  3. CO ₂²⁻, F ₂
  4. DCO , NO ⁺

Correct answer

C. O ₂²⁻, F ₂

Step-by-step solution

Among the given isoelectronic species, O ₂²⁻ and F ₂ contains 18 e⁻ each and their bond order is 1. For O ₂²⁻ B O = N_b-N_a 2 = 10-8 2 =1 For F ₂ B.O = N_b-N_a 2 = 10-8 2 =1

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