KCET2015ChemistryHydrocarbons
The hydrolysis of optically active ( 2 )-bromobutane with aqueous ( NaOH ) result in the formation of
Options
- A( (+) ) butan-2-ol
- B(-) butan-2-ol
- C( ( ) ) butan-1-ol
- D( ( ) ) butan-2-ol
Correct answer
D. ( ( ) ) butan-2-ol
Step-by-step solution
2-Bromobutane is a secondary alkyl halide, therefore, hydrolysis will proceed through ( S_ N 1 ) mechanisms, hence, racemic mixture will be formed, that is, (±) butan-2-ol. (+) Butan-2-ol (-) Butan-2-ol