KCET2014ChemistryIonic Equilibrium
The correct arrangement of the species in the decreasing order of the bond length between carbon and oxygen in them is
Options
- A( CO ₂, HCO ₂⁻, CO , CO ₃²⁻ )
- B( CO , CO ₃ ²⁻, CO ₂, HCO ₂ )
- C( CO , CO ₂, HCO ₂⁻, CO ₃²⁻ )
- D( CO ₃ ²⁻, HCO ₂ ⁻, CO ₂, CO )
Correct answer
D. ( CO ₃ ²⁻, HCO ₂ ⁻, CO ₂, CO )
Step-by-step solution
We know Bond order ( 1 Bond length ) CO molecule have ( 3 ) bonds between ( C ) and ( O ). [ C=O ] ( CO ₂ ) molecule have ( 2 ) double bonds between ( C ) and ( O ) [ O=C=O ] ( CO ₃ ²⁻ ) ion have ( 3 ) partial double bonds between ( C ) and ( O ), due to resonance. ( HCO ₂ ⁻ )ion also show resonance, but due to the presence of hydrogen atom attached to carbon atom it has less resonance hybrid, therefore, ( HCO ₂ ⁻ )ion have greater bond order than ( CO ₃ ²⁻ ) Hence, the correct decreasing order of bond length is (