1 dm ³ solution containing 10⁻⁵ moles each of Cl ⁻ ions and CrO ₄²⁻ ions is treated with 10⁻⁴ moles of silver nitrate. Which one of the following observations is made? aligned [ K _ sp Ag ₂ CrO ₄ . & .=4 10⁻¹² ] [ K _ sp AgCl . & .=1 10⁻¹⁰ ] aligned

Step-by-step solution

For precipitation, ionic product > solubility product ( K _ sp ) For Ag ₂ CrO ₄ aligned ionic product &= [ Ag ⁺ ]² [ CrO ₄⁻ ] &= (10⁻⁴ )² (10⁻⁵ )=10⁻¹³ aligned K _ sp of Ag ₂ CrO ₄=4 10⁻¹² Here, K _ sp > IP Thus, no precipitate is obtained. For AgCl , ionic product = [ Ag ⁺ ] [ Cl ⁻ ]= [10⁻⁴ ] [10⁻⁵ ]=10⁻⁹ K _ sp ( AgCl )=1 10⁻¹⁰ Here, IP > K _ sp So, precipitate will form. Thus, silver chloride gets precipitated first.