( 0.44 ~g ) of a monohydric alcohol when added to methylmagnesium iodide in ether liberates at S.T.P., ( 112 ~cm ³ ) of methane. With PCC the same alcohol forms a carbonyl compound that answers silver mirror test. The monohydric alcohol is

Step-by-step solution

At STP 112 ~cm ³ of methane liberated, 22400 ~cm ³=1 ~mol at ST 1 ~cm ³= 1 22400 ~mol 112 ~cm ³= 1 22400 112 ~mol =0.005 mol of methane liberated 1 mol of monohydric alcohol react with 1 mol of methyl magnesium iodide to produces 1 ~mol of methane, according to the reaction, Monohydric alcohol+ CH ₃ M gl - Either 0.005 mol of monohydric alcohol produces 0.005 mol of methane Now, molar mass of monohydric alcohol = Given mass of monohydric alcohol Number of moles of monohydric alcohol = 0.44 0.005 =88 ~g Monohydric a