KCET2025ChemistrySolutions
180 g of glucose, C ₆ H ₁₂ O ₆ , is dissolved in 1 kg of water in a vessel. The temperature at which water boils at 1.013 bar is ______ (given, K _ b for water is 052 ~K ~kg ~mol ⁻¹ . Boiling point for pure water is 373.15 K )
Options
- A373.67 K
- B373015 K
- C373.0 K
- D373.202 K
Correct answer
A. 373.67 K
Step-by-step solution
aligned & T _ b = i K _ b m ( i =1) glowse & T _ b -373.15=1 0.52 180 180 1 & ~T _ b =0.52+373.15=373.67 ~K aligned