If N ₂ gas is bubbled through water at 293 K , how many moles of N ₂ gas would dissolve in 1 litre of water? Assume that N ₂ exerts a partial pressure of 0.987 bar. [Given K _ H for N ₂ at 293 K is 76.48 K bar]

Step-by-step solution

Henry law :- P = K _ H X XN ₂= PN ₂ ~K ₄ = 0.987 76.48 10^3 =1.29 10⁻⁵ aligned & n _ H ₂ O = 1000 18 =55.5 & XN ₂= n _ N ₂ n _ N ₂ + n _ H ₂ O & 1.29 10⁻⁵= n n +55.5 = n 55.5 & n =1.29 10⁻⁵ 55.5 & n _ N ₂ =7.16 10⁻⁴ aligned