Vapour pressure of a solution containing 18 g of glucose and 178.2 g of water at 100^ C is (Vapour pressure of pure water at 100^ C =760 torr)

Step-by-step solution

Relative lowering of vapour pressure is equal to mole fraction of glucose. p₀-p_S p₀ = _ Glucose ...(i) Now, number of moles of glucose = 18 180 =0.1 number of moles of water = 178.2 18 =9.9 Mole fraction of glucose = 0.1 0.1+9.9 =0.01 Substituting the value of mole fraction in Eq. (i) 760-p 760 =0.01p=752.4 torr 752.0 torr