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The rise in boiling point of a solution containing 1.8 ~g of glucose in 100 ~g of solvent is 0.1^ C . The molal elevation constant of the liquid is

Options

  1. A1 ~K ~kg / mol
  2. B2 ~K ~kg / mol
  3. C10 ~K ~kg / mol
  4. D0.1 ~K ~kg / mol

Correct answer

A. 1 ~K ~kg / mol

Step-by-step solution

Given, amount of glucose (w)=1.8 ~g Amount of solvent (W)=100 ~g T_b=0.1^ C Molecular mass of glucose =180 Molal elevation constant of the liquid, T_b=0.1^ C We know that, aligned K_b & = T_b m W 1000 w & = 0.1 180 100 1000 1.8 =1 ~K ~kg / mol aligned

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