Henry's law constant for the solubility of N ₂ gas in water at 298 ~K is 1.0 10⁵ ~atm . The mole fraction of N ₂ in air is 0.8 . The number of moles of N ₂ from air dissolved in 10 moles of water at 298 ~K and 5 atm pressure is

Step-by-step solution

Given, Henry's law constant (K_ H ) for the solubility of N ₂ gas in water at 298 ~K =1 10⁵ atm. Mole fraction of N ₂ ( _ N ₂ )=0.8 Hence, partial pressure of nitrogen, aligned p_ N ₂ &=p_ total _ N ₂ &=0.8 5 ~atm &=4 ~atm aligned According to Henry's law, aligned p_ N ₂ &=K_ H _ N ₂ 4 &=10⁵ _ N ₂ _ N ₂ &=4 10⁻⁵ aligned We know that, aligned _ N ₂ &= n_ N ₂ n_ N ₂ +n_ H ₂ O 4 10⁻⁵ &= n_ N ₂ 10 ( n_ N ₂ << < n_ H ₂ O ) n_ N ₂ &=4 10⁻⁴ moles aligned Thus, the number of moles of N ₂ from air dissolved in 10 moles of w