KCET2021ChemistrySolutions
The vapour pressure of pure liquids A and B are 450 and 700 ~mm of Hg at 350 ~K respectively. If the total vapour pressure of the mixture is 600 ~mm of Hg , the composition of the mixture in the solution is
Options
- A_ A =0.4, _ B =0.6
- B_ A =0.6, _ B =0.4
- C_ A =0.3, _ B =0.7
- D_ A =0.7, _ B =0.3
Correct answer
A. _ A =0.4, _ B =0.6
Step-by-step solution
Given, vapour pressure of pure liquid A , p_ A ^ =450 ~mm of Hg Vapour pressure of pure liquid B , p_ B ^ =700 ~mm of Hg Total vapour pressure, p_ Total =600 ~mm of Hg From Raoult's law, p_ Total =p_ A ^ _ A +p_ B _ B aligned &-p_ A ^ _ A +p_ B ^ (1- _ A ) 600 &=450 _ A =700 (1- _ A ) &=450 _ A +700-700 _ A &=700-250 _ A 250 _ A &=700-600 _ A = 100 250 _ A &=0.4 _ B &=1-0.4=0.6 aligned