KCET2019ChemistrySolutions
Relative lowering of vapour pressure of a dilute solution of glucose dissolved in ( 1 ~kg ) of water is ( 0.002 ). The molality of the solution is
Options
- A( 0.111 )
- B( 0.021 )
- C( 0.004 )
- D( 0.222 )
Correct answer
A. ( 0.111 )
Step-by-step solution
(A) [ array l P^ -P P^ = W₂ M₂ M₁ W₁ 0.002= W₂ M₂ 18 1000 W₂ M₂ =0.11 mole array ] [ Molality = W₂ M₂ 1000 W₁ =0.11 1000 1000 =0.11 ~m ]