KCET2007ChemistrySolutions
The volume of 10 ~N and 4 ~N HCl required to make 1 ~L of 7 ~N HCl are
Options
- A0.50 ~L of 10 ~N HCl and 0.50 ~L of 4 ~N HCl
- B0.60 ~L of 10 ~N HCl and 0.40 ~L of 4 ~N HCl
- C0.80 ~L of 10 ~N HCl and 0.20 ~L of 4 ~N HCl
- D0.75 ~L of 10 ~N HCl and 0.25 ~L of 4 ~N HCl
Correct answer
A. 0.50 ~L of 10 ~N HCl and 0.50 ~L of 4 ~N HCl
Step-by-step solution
Let V litre of 10 ~N HCI be mixed with (1-V) litre of 4 N HCl to give (V+1-V)=1 ~L of 7 ~N HCl . aligned N₁ V₁+N₂ V₂ &=N V 10 V+4(1-V) &=7 1 10 V+4-4 V &=7 6 V &=7-4 V &= 3 6 =0.50 ~L aligned Volume of 10 ~N HCI =0.50 ~L Volume of 4 ~N HCl =1-0.50=0.50 ~L