KCET2011ChemistryStates of Matter
The folllowing data were obtained during the first order decomposition of 2 A(g) B(g)+C(s) at a constant volume and at a particular temperature The rate constant in min ⁻¹ is
Options
- A0.0693
- B69.3
- C6.93
- D6.93 10⁻⁴
Correct answer
A. 0.0693
Step-by-step solution
array lc 2 A(g) B(g)+C(s) 2-2 x & x array At the end of reaction, only 1 mole of gas is present whose pressure is 200 Pascal. At the beginning of the reaction 2 moles of gas should have a pressure of 400 Pascal. After time 10 ~min No. of moles present, 2-2 x+x=2-x The pressure of 2 moles =400 400-x=300 x=100 Pressure due to 2-2 x moles of A =400-200=200 aligned k &= 2.303 t ( a a-x )= 2.303 10 ( 400 200 ) &= 2.303 10 2= 0.693 10 &=0.0693 ~min ⁻¹ aligned